n^2=5625

Solution for n^2=5625 equation:

n^2=5625

We move all terms to the left:

n^2-(5625)=0

a = 1; b = 0; c = -5625;
Δ = b2-4ac
Δ = 02-4·1·(-5625)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*1}=\frac{-150}{2}
=-75
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*1}=\frac{150}{2}
=75
$